tool 2079, how torque works

[Matt Evans]

so we're talking about this thing, right ?

http://cgi.ebay.com/ws/eBayISAPI.dll?ViewItem&item=2541588343&category=42337

and the socket end goes on the crank nut ?

what do you attach to this tool ? (or what does it attach to ?)

i don't really know how to make it any simpler than this.  if you've got
a wrench 1 foot long, and at a 90 degree angle to the end of that wrench,
you push with 100 pounds of force, you've created 100 ft/lbs.  if you have
a wrench 2 feet long, and you push in the middle of the wrench with 100 pounds
you've got 100 ft/lbs.  if you go to the end of the 2 foot wrench and push
with 100 pounds, you've got 200 ft/lbs.  if you make the wrench 3 feet long
and push at the end, you've got 300 ft/lbs.

if you push at some angle thats not orthoganol to the lever arm, you dont
get the full transmission of the force as torque, because you've really got
a force vector and you only get the perpendicular component of that force.

if attaching two tools together somehow creates an elbow instead of a straight
connection, the force needs to be applied orthoganol to the imaginary line
through the socket to the point of application, regardless of what path the
tool makes.  this imaginary line is also the length of the effective lever arm
, again, regardless of what path/shape the tool is.

hopefully someone can point out the controvery to me, because im not getting
it :)