[s-cars] Multiplier for Dyno

[calvinlc at earthlink.net]

For instance, torque=inertia*angular acceleration.  If you are trying to
accelerate a given inertia, i.e. a flywheel, but you are trying to
accelerate it faster, that is you are applying more torque, then the amount
of loss becomes greater.  And of course since the acceleration of the
component is directly proportional to the overall acceleration of the
system, the amount of torque lost in accelerating that component is also
proportional to the overall acceleration of the system.  Thus it can be
expressed as a percentage of the total torque produced.

There are some factors that are constant, but they are much smaller players.

--Calvin


-----Original Message-----
From: s-car-list-bounces at audifans.com
[mailto:s-car-list-bounces at audifans.com]On Behalf Of Daniel Koropchak
Sent: Friday, April 07, 2006 9:17 PM
To: CaptMagu at aol.com; s-car-list at audifans.com
Subject: Re: [s-cars] Multiplier for Dyno


How is it that driveline loss does not remain constant ?

CaptMagu at aol.com wrote:  Dan

We don't use noh Steenkin multipliers. Oops, I live in Colorado. Oh yeah,
use whatever you want the guy to plug in. Seriously, the number for going
from wheel to crank is 20% for drivetrain loss. Most guys post ATW numbers.
Factored for a variety of dreams ;-)

Hap, wit dakine Colorado numbahs not from Evahboost, Maguire


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