[s-cars] Off topic - New Volvo S60 ? - Drat and double DRAT!
Robert Myers
bob at chips-ur-s.com
Wed Jan 5 16:24:22 PST 2011
*This message was transferred with a trial version of CommuniGate(r) Pro*
Thus respondeth the newly acclaimed Haldex Boy. :-D
Bob
At 07:03 PM 1/5/2011, qshipq at aol.com wrote:
>*This message was transferred with a trial version of CommuniGate(r) Pro*
>
>
> They aka'd me 'Torsen Boy' for a reason, I'm pretty nerdy about
> how differentials and locking axle 4wd systems work, it's my thing
> I guess, has been for many years. I get really picky when
> incorrect terms are used for a relatively simple concept. It's
> just plain incorrect to state that power is 50f/50r on ANY center
> differential or locked axles with a single, sole and only
> exception: An open differential will ALWAYS distribute power 50/50
> to two axles, regardless of variables, period. Which means
> specifically, no other differential or locked axles can, other than
> in theory. If all the variables are just right, a locked Haldex
> can pass thru a 50f/50r power split state in theory. Any other
> moment in time or input variable, it's not.
>
>By theory it can I mean you go back to how a Haldex works,
>specifically what's making it 'lock up'? It's a combination of
>variables that makes the 50/50 nary impossible in that locked up
>state. What you state in your 50f/50r is the commonly accepted way
>to define an open differential, it's not really a property or
>description of a Haldex.
>
>Technically, your description of a gen 1 quattro is not correct
>either. To the Haldex locked in a straight line (simple
>example): If torque follows weight transfer in a locked f/r axle
>quattro in a straight line on a hi cf track, how exactly can you
>ever be 'roughly equal to all wheels with infinite traction"? There
>is no such thing Cody, torque will only be equal if you are coasting
>where Trg (torque ring gear) = 0. As soon as you speed up or slow
>down, torque follows weight transfer again. Add Hap 670hp foot to
>the floor or jam a set of Big Reds, torque to the axles is not
>roughly equal, not even close.
>
>Cheers
>
>S 'torsen boy' J
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>-----Original Message-----
>From: John Cody Forbes <cody at 5000tq.com>
>To: qshipq at aol.com <qshipq at aol.com>
>Cc: t44tqtro at gmail.com <t44tqtro at gmail.com>; mtgadbois at aol.com
><mtgadbois at aol.com>; pkrasusky at ups.com <pkrasusky at ups.com>;
>s-car-list at audifans.com <s-car-list at audifans.com>
>Sent: Wed, Jan 5, 2011 1:07 pm
>Subject: Re: [s-cars] Off topic - New Volvo S60 ? - Drat and double DRAT!
>
>
>Talking about power/torque splits is always going to be confusing
>because it depends on so many factors. In theory a gen1 quattro with
>all the locks on CAN put 100% power to any single rear wheel, the
>rears as a pair, the fronts as a pair, or 3 wheels as long as two of
>them are in the rear. I fully understand what you are saying and
>agree, but I chose to go with the commonly accepted way of conveying
>the point. With infinite tire traction the power is going to be
>roughly equally distributed between all of the wheels when the
>Haldex is engaged. When disengaged the Haldex is basically as if you
>removed the prop shaft. Except for oil friction there is zero force
>being transmitted from the transmission to the rear diff. Thus is
>why it is completely safe to tow a Haldex car with the rear axle on
>the ground and the front lifted. According to VW you can even dyno a
>Haldex car as if it was front wheel drive.
>
>
>My initial statement may have left out that when I said "clutch is
>engaged" I meant the Haldex clutch pack, yes. The point stands that
>when the Haldex clutches are fully engaged with no slip (slipping
>the Haldex is a possibility, but pretty remote except for extreme
>circumstances) the rear diff is tied solidly to the transmission
>output shaft, and most lay persons will see that as being tied to the engine.
>
>-Cody (mobile)
>
>On Jan 5, 2011, at 12:12 PM, qshipq at aol.com wrote:
>
>
>
>
> Cody
>"50/50 power split" is the most common mis-statement about locked
>axles, not oversimplified, just not correct on any level or
>description of locked axles. Not sure your question if you reread
>your statement below. The rear prop shaft is ALWAYS connected to
>the transmission and is always spinning at the input of the Haldex
>in the rear diff. When the coupler is engaged there absolutely can
>be slippage, my point to your simple exact statement "when the
>clutch is engaged the rear wheels are completely locked to the
>engine". That's just not correct as written. I suspect what you
>meant to write was "When the Haldex is fully locked, the rear
>differential is completely locked to the prop shaft
>(transmission/input axle)". To exactly what you wrote on the other
>hand, when the clutch is engaged the rear wheels are not 'locked' to
>anything. Specifically the rear axles can slip in relation to the
>input shaft speed up to fully locked = any state less than a fully
>locked up Haldex coupler.
>
>HTH
>
>SJ
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