[Vwdiesel] Miser's method elaborated :o)

[Mark Shepherd]

The LED's are not in series with G/Ps but attached in parallel with the individual(ized) supplys Just like an ammeter shunt 99.99% of current would go through the copper supply wire with a little going through the diode . It could be worked out mathematically; but buy 6 cheap LED's t o allow for failed 2 iterations. Say a shunt of 6 inches of sample supply wire 
+_____________________i====> G/P
              |                                 |
              |_______i<i______|
                          LED

Miser