[Author Prev][Author Next][Thread Prev][Thread Next][Author Index][Thread Index]

No Subject



>>From: "R. Cummings" <cumm@flash.net>
>Date: Wed, 26 Feb 1997 16:52:17 -0600 (CST)
>Subject: I'm Torqued Off
>
>Wow! this torque thing has got a lot of play. Some folks are right, some are
>wrong. First the derivation, then the example.
>If:
>L1 = length of extension - ft. (ctr. of socket to ctr. of hole for torque
>wrench)
>L2 = Length of torque wrench - ft. (point of force on handle to center of sq.)
>Indicated torque = 258 ft lbs
>F = force applied to torque wrench to get 258 ft lbs indicated torque - lbs.
>Then:
>F= 258/L2  force = indicated torque/length of handle
>Torque on nut = F*(L1+L2).

>
>Bob Cummings
>

Torque on nut = (torque setting on wrench) x (L1+L2)/L2

The length L2 of the torque wrench IS IMPORTANT.
Finally the correct answer, well explained. Thanks Bob.

I just got back from the SAE show, and waded through 6 digests
of torque wrench theories.... was about to set the record straight
then I saw Bob's posting.