That's right, absolutely NAC. Electrical question
Richard J Lebens
rick-l at rocketmail.com
Thu May 30 13:45:33 PDT 2013
Start out in a perfect world - 100% efficiency. The rated output of the supply is 24 @ 3.75 Amps which works out to 90 Watts. (It probably does not run at it's rated output) 90 Watts at 12 volts will require 7.5 Amps. 8 hours would use 60 Amp-hours which seems to be within a 12 volt deep cycle battery capability.
Now the real world Guess (I have no clue) that the 24 volt supply is 85% efficient, the inverter 60% which will require 177 Watts at 12 volts or 14.7 amps, beyond the capability of a battery. Now if the device only needs half that 3.75 Amps you have a much better situation.
Of course a boost regulator that gets rid of all that inefficiency would work a lot better but that would cost money.
Somebody check my math.
1. NAC. That's right, absolutely NAC. Electrical question
(John Larson)
So I have this former customer, a charity case, pretty much, with a
sleeping/breathing problem. He lives in a 1970 VW bus with only
occasional access to 110v power. He uses a respiration helper device
when he sleeps. I have the label for the power supply (which has a 24v
output at 3.75A), and I need to figure out what kind of load that'll put
on a 12 battery through a 400w 90A inverter. He already has the
inverter so we want to try to use it. I'm planning to install some kind
of battery isolator, possibly a Ford starter relay (of which I have a
number) activated by the KOEO position on the ignition switch. If it
would be better, I can purchase a dedicated component. I'm planning on
using a deep cycle battery and keeping it charged with the alternator
(and possibly a solar panel, if necessary). I know there are some of
you that can do the math while walking and chewing gum, so this one
should be a breeze! I'm not one of those people ...................
Would it be better to just use a 12vDC>24vDC device and forgo the
12vDC>110ACv>24vDC?
Cost effective way? Best way?
Thanks! John
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