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homework- steadimath example
> * S.O.c claims and audi facts:
> * 26psi in 2nd thru 5th
> * 2.5 bar PT
> * 16+psi in 1st gear
> * .5 PD accross modded IC
> * Audi --> RS2 gets 310hp @ 460CFM
> * 1325 EGT
> * Audi --> MC motor = 134ci
>
> The homework would be
> A) How does a 134ci motor flow 513CFM in 10v trim? Can it?
> B) Why such a large PR? I thought Density Ratio was more the goal?
>
engine displacement
D=135.8 in^3
engine speed
w=5500 rpm
ideal air flow of n/a engine, VE = .85
Fi = 216.1* .85 = 183.7 cfm
ambient temp
Ta = 70 degF
boost pressure
Pb = 26 psi
ambient air pressure
Pi = 14.7
Pressure ratio
Pr = 2.77
ideal temp gain
Tgi = 177 degF
turbo eff = .72
actual temp gain
Tg = Tgi/.72 = 246 degF
turbo outlet temp
To = Ta+Tg = 316 degF
air density ratio
Rd = (530/776)*2.77 = 1.89
modded I/C eff = .834
i/c temp reduction
Tir = 246*.834 = 205 degF
intake manifold air temp
Tm = 316-205 = 111 degF
net air temp rise
Tr = 111-70 = 41 degF
intake track efficiency
Eintake = 530/571 = .93
net air density ratio in intake manifold
Rm = 2.77*.93 = 2.57
effective air flow
Fe = Fa*Rm = 183.7*2.57 = 473.2 cfm
Dr. science's hand calc showed 184*2.79 = 513cfm.
Mine is a bit lower given the revised air density number when taking
the temperature increases and decreases into account. It is
< 10% delta effect using the short form, and pretty close given the
back-o-the-envelope calculations.
Lots of RDEs for initial conditions, that I/C efficiency is one that I
didn't check, just used a previous assumption.
Now why is any of this important? The goal here is to get the greatest
volume of the coldest(densest) air we can, and cram it into our
cylinders.
When you go for greater volume, the temperature goes up and density
goes down, and you will eventually reach the point where the volume
increase is negated by the hotter, less dense air.
-
Dave